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	<title>Half-Byte &#187; laser</title>
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	<link>http://half-byte.com</link>
	<description>Doing more with less.</description>
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		<title>Laser Powering a Solar Cell Experiment</title>
		<link>http://half-byte.com/2010/01/07/laser-powering-a-solar-cell-experiment/</link>
		<comments>http://half-byte.com/2010/01/07/laser-powering-a-solar-cell-experiment/#comments</comments>
		<pubDate>Thu, 07 Jan 2010 21:45:03 +0000</pubDate>
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				<category><![CDATA[News]]></category>
		<category><![CDATA[cell]]></category>
		<category><![CDATA[experiment]]></category>
		<category><![CDATA[laser]]></category>
		<category><![CDATA[light]]></category>
		<category><![CDATA[panel]]></category>
		<category><![CDATA[photovoltaic]]></category>
		<category><![CDATA[sensor]]></category>
		<category><![CDATA[solar]]></category>

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		<description><![CDATA[<p>How much current does a simple over the counter five dollar laser produce when hitting a small solar panel?  I wasn&#8217;t sure, so I did a little experiment.</p> <p>Using my handy multimeter, I determined the laser circuit was 4.5V at 25 mA.  Since W = V * A, 4.5V x 25mA is 112.5mW.  Now [...]]]></description>
			<content:encoded><![CDATA[<p>How much current does a simple over the counter five dollar laser produce when hitting a small solar panel?  I wasn&#8217;t sure, so I did a little experiment.</p>
<p><a href="http://www.half-byte.com/wp-content/uploads/2010/01/laser_base.png" title="Base Reading"><img src="http://www.half-byte.com/wp-content/uploads/2010/01/laser_base.thumbnail.png" alt="Base Reading" align="left" hspace="10" /></a>Using my handy multimeter, I determined the laser circuit was 4.5V at 25 mA.  Since W = V * A, 4.5V x 25mA is 112.5mW.  Now that&#8217;s just the internal circuit power.  There&#8217;s a sticker on the the cheap-o laser explaining the laser output is &lt; 5mW.</p>
<p>I had a small <a href="http://www.allelectronics.com/index.php?page=search&amp;search_query=solar&amp;x=0&amp;y=0" title="photovoltaic sensor" target="_blank">photovoltaic sensor</a> from <a href="http://www.allelectronics.com" title="All Electronics" target="_blank">All Electronics</a>, that has an output of about 0.5 volts.  When placed under a lamp it produced 2mA of current.</p>
<p><a href="http://www.half-byte.com/wp-content/uploads/2010/01/laser_on_correct.png" title="Laser Reading"><img src="http://www.half-byte.com/wp-content/uploads/2010/01/laser_on_correct.thumbnail.png" alt="Laser Reading" align="right" hspace="10" /></a>When the laser was directed on the sensor, the current registered 4.5mA.  This means 0.5V x 4.5mA is 2.25mW.</p>
<p>The reading includes the background lamp light, so the power generated by the laser hitting the cell is much less.  A lot of the light was lost due to reflection, but my objective wasn&#8217;t to test the light output of the laser.  I really wanted to see how much power could be generated on the solar cell side.</p>
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